import java.util. Language ); break; } } if(flag==false) { System.out.println(**** Invalid Product Number ****); } System.out.println(Press 1 if you want to remain in scrap); again=sc.nextInt(); } while(again==1); }. I put the code same as in the video but the android shows an error: array required, but int found. 2: This could be read from a file. How can i fix this ? ); break; } } if(flag==false) { System.out.println(**** Invalid Product ID ****); } }, void register() { System.out.println(Your customer ID is: +id2); id2++; }. Credits */, /* Name of the class has to be "Main" only if the class is public. Swift MODIFY); System.out.println(); System.out.println(tttt 5. here is my codecan anybody tell me whats wrong at line 272 at line 272 there are two errors array required but java.lang.string found cannot find symbol method . "Array required but string found" error when trying to create a new File EDIT: This has been resolved. You can instead use original.charAt (i) to read a character at an index. 2 Answers Sorted by: 18 You can't use array subscripts: [], to index into a String, and both hidden and original are Strings. java - : Array required, Stack Overflow . Computer Science questions and answers. ); } if(ob.out==0) { System.out.println(Enter 1 to remain in the MAIN MENU.); ob.again=sc.nextInt(); } } while(ob.again==1); System.out.println(); System.out.println( Thank You for visiting! EXIT); System.out.println(); System.out.println(tttt 8. . // below I assume one word per line and store the same in the dictionary[] array. I have no previous language experience, so will be referring to this list often. chickenmeister 10 yr. ago it says it may not have been initialized, however, I clearly wrote "int value1" at the top of my program. name name add . . 1 2 3 for( Employee employee : list ) { . Perl Consider renaming the parameters to your method, or using the class name to reference them. Expert Answer PLEASE GIVE IT A THUMBS UP, I SERIOUSLY NEED ONE, IF YOU NEED ANY MODIFICATION THEN LET ME KNOW, I WILL DO IT FOR YOU 1st error Corre View the full answer Transcribed image text: Main.java E Console Shell //int cLength= correct.length; String thisAns; > javac -classpath . Python3 tiny ads are for attractive people. Recommended Answers. *; public class BeautyParlour { Scanner sc= new Scanner(System.in); int idd=4; int id2=5; int b_cost, c_b_sr, c_b_cost, out, again, d, psr, m, pid, cid, x, cuid; String b_type ,b_b_type ,c_b_type ,c_b_b_type ,ss ,a ,b ; char b_scp; double bill; int b_sr[]; int i; public static void main() { int ch; BeautyParlour ob= new BeautyParlour(); Scanner sc= new Scanner(System.in); do { System.out.println(f); System.out.println(); System.out.println(); System.out.println(); System.out.println(); System.out.println(tttt -BEAUTY PARLOUR-); System.out.println(tttt 1. API I'm new to Java and not very good at it. Pay close attention to how you're using your variables. (actual and formal argument lists differ in length) 9 errors. help me plz 18th Sep 2017, 4:01 PM Answer Array required, but java.lang.String found..what does this mean??? : ); int psr=sc.nextInt(); boolean flag= false; int i; for( i=0; i= 2001 && bill <= 3500) { System.out.println( You are eligible for a 10% discount. C++14 You have a collision between the static name String array and the local name String variable passed to the add method. straws are for suckers. if(flag==true) { String ss= sc.nextLine(); b_sr[i]=i+1; System.out.println(Your next product ID is: +(i+1)); System.out.println(); System.out.println(Enter the type: ); String a=sc.nextLine(); b_type[i]=a; System.out.println(Enter the Category: ); String b= sc.nextLine(); b_b_type[i]=b; System.out.println(Enter the cost: ); int d=sc.nextInt(); b_cost[i]=d; } }. error: array required, but String found This assignment requires a program that asks a customer for their burger order and outputs the order and price. Array Required, but java.lang.String found. I put the code same as in the video but the android shows an error: array required, but int found. Errors : ArrayListString.java:27: cannot find symbol symbol : variable length location: class java.util.ArrayList<java.lang.String> for(int i = 0; i < arraylistStr.length; i++) ^ BILL); System.out.println(); System.out.println(tttt 6. void loading() { System.out.println(LOADING); int m=1; long i; for(i=1;i<=100000000;i++) { if (m==100000000) { m=1; System.out.println(.); void modify() { menu(); System.out.println(); System.out.println(Enter the product ID: ); int pid= sc.nextInt(); for(i=0; b_sr.length;i++) { if(pid==b_sr[i] && b_scp[i]==n) { flag=true; System.out.println(The current price is: +b_cost[i]); System.out.println(); System.out.println(Enter the price to be modified: ); b_cost[i]=sc.nextInt(); System.out.println(); System.out.println(The new price has been updated successfully. ? It would make the code much easier to understand. SQLite ERRORS: Car.java:18: error: array required, but String found carMakes [i] [1]=" "; ^ Car.java:28: error: array required, but String . I can't figure out how to fix the errors that I'm getting here. :/run_dir/junit-4.12.jar:target/dependency/* -d . You can't use array subscripts: [], to index into a String, and both hidden and original are Strings. The same is true for id; it is an int, but you're doing an array element access on it. The brand new service which powers Ideone! FACILITY); System.out.println(); System.out.println(tttt ENTER YOUR CHOICE > ); ch=sc.nextInt(); switch(ch) { case 1: ob.menu(); break; case 8: ob.out=1; ob.again=0; break; default: System.out.println(Invalid choice. Below are the errors I am getting and the code. List of all supported programming languages, 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, /* package whatever; // don't place package name! Don't duplicate the code in lines1217; use a loop or a Stream. I am trying to build a program where I am sorting Student Names and Test scores in arrays. Terms of Service Here is my code: C I took a look at the video and he is parsing a String array with hex colors to an int. When we have that and everyone agrees it is a reasonable design . @2010_shreyy Sep 30.2021 import java.util. if we the first symbol we have in copy string found twice in another string (both contain same symbols) return true, else false; But I am getting error "Array required but string found" Any ideas?? Tool completed with exit code 1. Pascal array required, but int found @Debindigo Apr 22.2005 Hi there, I'm new to the list and am a newbie in the Java language. GDPR Info, Bash Don't you know how to write either loops or Streams? desktop Haskell ); void facility() { System.out.println(f); int conti3; int choice3; menu(); if(id2>5) { System.out.println( Your customer ID is +(id2-1)); do { boolean flag= false; System.out.println( Enter the choice of the facility you want: ); choice3 = sc.nextInt(); for( int i=0; i=2000) { System.out.println(You are eligible for a 5% discount. Norm Radder wrote:. What do I do? Home Trying to make the questions equal each message dialog and for each answer to equal each question. VB.net . . 1 . How are your. ADD); System.out.println(); System.out.println(tttt 3. divinity wrote. void add() { menu(); int i; boolean flag = false; for(i=0;i <\/a>'].join('')); I've declared public static arrays for name and id: I don't know what's wrong. The parameters to my main method were incorrect. Python ,(): . An array in Java is a group of like-typed variables referred to by a common name. Help @2010_shreyy spread the word by sharing this article on Twitter how could be use unicode charater on button. Use a loop that accesses the next Quiz item, asks the user the question, reads the user's response and compares that to the answer in the Quiz class. I understand the concepts, but how do I put that code together. would really appreciate it if anyo. void menu() { int i; System.out.println(f); System.out.println(tttt MAIN MENU ); System.out.println(); System.out.println(); System.out.println(); System.out.println(tt); System.out.println(tt|srno.t|typet|catt|cost|); for(i=0;i=1000 && c_b_cost[i]<2000) { System.out.println( You are eligible for gift voucher of Rs. DJTable JTableJava.lang.String found String DString adsbygoogle window.adsbygoogle .push C:\GameApp.java:13: error: array required, but String found
ques[0] = JOptionPane.showInputDialog("what is the answer to question1"); Campbell Ritchie wrote:Don't duplicate the code in lines1217; use a loop or a Stream. . . MENU CARD); System.out.println(); System.out.println(tttt 2. REMOVE); System.out.println(); System.out.println(tttt 4. You're effectively shadowing your static variables, which causes confusion and heartache. A String is not an array of characters in Java (in this Java differs from for example C and Pascal). Reverse string in java String s="hello"; int length=s.length (); String s1=""; for (int j=1;j<=length; j++) { s1+=s [length-j]; // shows me error here ..array required but string found System.out.println (s1); } how to rectify it?? ); bill=bill-bill*0.15; } } }, void gift() { int i; System.out.println(Enter Customer ID: ); int cuid=sc.nextInt(); for(i=0; i=0 && c_b_cost[i]<500) { System.out.println( Sorry, You are not eligible for a gift voucher); }, else if(c_b_cost[i]>=500 && c_b_cost[i]<1000) { System.out.println( You are eligible for gift voucher of Rs. Arrays in Java, getting 'array required, but arrayList<string> found' String (Enter) String iffor'x' () 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 import java.util.Scanner; C++ I have posted previously my code but ditched it since I didn't know how to proceed with it. method JOptionPane.showMessageDialog (Component,Object,String,int,Icon) is not applicable. ); bill= bill-bill*0.10; } else if (bill >=3501) { System.out.println(You are eligible for a 15% discount. 300 (Validity 2 months).); } else { System.out.println( You are eligible for gift voucher of Rs. 807605 Oct 15 2007 edited Oct 16 2007 Hi friends, For the following piece of code : bold for (int i=1; i <= studentClasses.length (); i++) { if (UICClassID.equals (studentClasses )) { canTakeThisCourse = false; return canTakeThisCourse; break; } bold It would make the code much easier to understand. void bill() { int cid; double dis=0.0; int i; double bill=0.0; int x=0; System.out.println(Enter Customer ID: ); cid=sc.nextInt(); for(i=0;i
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